15 in the chemical reaction where n2o4(g) is converted to 2no2(g), if 0.5 m n2o4 and 0.15 m no2 are present in the vessel, is the reaction at equilibrium? if not, which direction would the reaction proceed? (kc = 4.4 × 10-3) n2o4(g) 2no2(g) no, q = 9.0 × 10-2 so the reaction should proceed in the reverse direction. no, q = 0.18 so the reaction should proceed in the forward direction. no, q = 4.5 ×10-2 so the reaction should proceed in the reverse direction. yes, the reaction is at equilibrium.

the correct answer is=No, Q = 4.5 ×10-2 so the reaction should proceed in the reverse direction, just answered it ;

Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied