In the reaction mg (s) + 2hcl (aq) -> h2 (g) + mgcl (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of 1.0 m hcl in an access of mg?

Step One
Find the moles of HCl
C = 1.0 mol/L
V = 75 mL = 75 / 1000 = 0.75 L 
Note the concentration is in Liters.

Formula
n = C*V 

Solve
n = 1.0 * 0.075 
n = 0.075 moles

Step two 
Adjust the number of moles of HCl
How every mol of H2 produced, you will require 2 mol of HCl



2/1 = 0.075/x  Cross multiply
2x = 0.075      Divide by 2
x = 0.075 / 2
x = 0.0375      moles of H2  <<<<<<<<< Answer

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