What is the value of the equilibrium constant for this redox reaction? 2ag+(aq) + zn (s) → 2ag (s) + zn2+(aq) e = +1.56 v k=10(ne∘0.0592) k = 2.25 × 10-26 k = 2.25 × 1026 k = 5.04 × 10-52 k = 5.04 × 1052

Correct  Option D, K = 5.04 × 10^52

Reason:
We know that, 
Ecell = ,
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = +1.56 v

Therefore, 1.56 = 
Therefore, log (K) = 52.703
Therefore,  K = 5.04 X 10^52