1. the diagram shows an electrochemical cell with a gold strip (left) and aluminum glasses (right). in your response, do the following: • label all parts. • label the cathode and the anode, including the charge on each. • show the flow of electrons. • describe what type of electrochemical cell is pictured and what its use is. • explain how the cell works. include the oxidation and reduction half-reactions in your explanation.

Answer 1: 
 All parts in the electrochemical cells are labeled in second figure. Following are the part in electrochemical cells
1) Anode 2) Cathode 3) gold Stripe (Electrode) 4) Aluminium Glasses (Electrode) 5) Connecting wires 6) Battery.

Answer 2: 
Anode and Cathode  are labeled as 1 and 2, respectively in second diagram. Charge on anode is positive, while that on cathode is negative. The charges have been shown in figure. Further, it may be noted that, oxidation occurs at anode and reduction occurs at cathode.

Answer 3: 
Electricity flow from positive terminal of cell to negative terminal of cell. Same is show in blue colour in 2nd figure. Direction of flow of electron is opposition to flow of electricity. Thus, electrons flows from negative to positive.

Answer 4: 
Electrochemical cells are of two types
1) Electrolytic 
2) Galvanic
In electrolytic cell, electricity has to be applied for chemical reaction to occur. In galvanic cell, electricity is generated because of chemical reaction. 

The electrochemical cell in the diagram is an electrolytic cell.

Answer 5: 
The electrochemical cell in the diagram is an electrolytic cell which is used for gold plating. Electroplating is an electrolytic process that is use to coat metal objects with a more expensive and less reactive metal. The metal to be plated is kept as cathode, while metal whose plating is to be done is held as anode. 

Answer 6:
In the diagram, the gold strip is connected to the positive terminal of the battery and aluminum glasses is connected to negative terminal of the battery. Anode is positive electrode and cathode is negative.
When the power is switched on, the electrolyte solution splits into ions. Positively charged ion i.e. (Au³⁺) are attracted to the negatively charged electrode i.e. cathode. Due to this, gold is slowly deposited on aluminum glass. On other hand, negatively charged ions are attracted to positively charged electrode i.e. anode. Herein, Au goes into the solution at the anode and get reduced at the cathode. Due to this,  constant concentration of gold ions is maintained in the electrolyte solution.

Answer 7:
The  oxidation and reduction half-reactions involved in above electrochemical cell is shown below: 

Reaction at Anode: Au(s) → Au³⁺(aq) + 3e⁻ ................(oxidation)Reaction at Cathode: Au³⁺(aq) + 3e⁻ →Au(s) ..............(reduction)

Well technically there are two correct answers b and d. but for you its probably b in general.good day sir/ma'am : ) (i know not gender)