The following balanced equation shows the decomposition of ammonia (nh3) into nitrogen (n2) and hydrogen (h2). 2nh3 → n2 + 3h2 a quantity of nh3 decomposes to produce 0.0351 mol n2. how many moles of h2 are produced? 0.0351 mol h2 0.0117 mol h2 0.105 mol h2

The decomposition of ammonia is characterized by the following decomposition equation:
                                  2NH₃   →   N₂   +   3H₂   

The mole ratio of N₂  :  H₂  is  1  :  3

    If the number of moles of N₂  =  0.0351 mol
    Then the number of moles of H₂  =  0.0351 mol  × 3
                                                         = 0.1053 mol

The number of moles of hydrogen gas produced when 0.0351 mol of Nitrogen gas is produced after the decomposition of Ammonia is  0.105 mol (OPTION 3).