Asample that contains 4.78 mol of a gas at 251 k has a pressure of 1.19 atm. what is the volume? answer in units of l.

            V  =  81.86 L

Solution:

Data Given;
                   P  =  1.19 atm

                   n  =  4.78 mol

                   T  =  251 K

Let suppose the gas is acting ideally, then according to Ideal Gas Equation,

                                         P V  =  n R T

Solving for V,
                                         V  =  n R T / P

Putting Values,
                             
             V  =  (4.78 mol × 0.0812 L.atm.mol⁻¹.K⁻¹ × 251 K) ÷ 1.19 atm

             V  =  81.86 L