What is the resulting pressure when you transfer gas from cylinder with a temperature of 22°c and the pressure of four atm into a container with a temperature of 65°c? assume volume remains constant.

             P₂  =  4.58 atm

Solution:
               According to Gay-Lussac's law ," the pressure of a given mass of an ideal gas at constant volume is directly proportional to absolute temperature".
For initial and final states of a gas, the relation is given as,

                                           P₁ / T₁  =  P₂ / T₂    (1)

Data Given;
                   P₁  =  4 atm

                   T₁  =  22 °C + 273  =  295 K

                   P₂  =  ??

                   T₂  =  65 °C + 273  =  338 K

Now, solving equation 1 for P₂,

                  P₂  =  P₁ T₂ / T₁

Putting values,

                  P₂  =  (4 atm × 338 K) ÷ 295 K

                  P₂  =  4.58 atm

It conforms what ever surface its in.