If you dissolve 89.0g of sodium sulfate in 1.5 l of water , what is the molarity of the resulting solution ?

             Molarity  =  0.4 mol.L⁻¹

Solution:

Molarity is given as,

                         Molarity  =  Moles / Volume of Solution
Also,
                         Moles  =  Mass / M.mass
So,
                         Molarity  =  Mass / (M.mass × Volume of Solution)

Data Given,
                   Mass  =  89 g

                   M.mass of Na₂SO₄  =  142 g.mol⁻¹

                   Volume  =  1.5 L

Putting Values,
 
                    Molarity  =  85 g ÷ (142 g.mol⁻¹ × 1.5 L)

                    Molarity  =  0.399 ≈ 0.4 mol.L⁻¹

The gas would begin to expand, and eventually the can would burst or explode.