The pressure in a sealed plastic container is 108 kpa at 41 degrees celsius. what is the pressure when the temperature drops to 22 degrees celsius? assume that the volume has not changed.

The new pressure will be 101.46 kPa.

Explanation:

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

where,

are initial pressure and temperature.

are final pressure and temperature.

We are given:

By using conversion factor:  

Putting values in above equation, we get:

Hence, the new pressure will be 101.46 kPa.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles