When chlorine is added to acetylene, 1, 1, 2, 2-tetrachloroethane is formed: 2cl2 (g) + c2h2 (g) → c2h4cl4 (l) how many liters of chlorine will be needed to make 75.0 grams of c2h2cl4?

             20 L of Cl₂

Solution:

The reaction is as follow,

                                   H₂C₂  +  2 Cl₂     →      H₂C₂Cl₄

According to equation,

       167.84 g (1 mole) H₂C₂Cl₄ is produced by  =  44.8 L (2 mole) of Cl₂
So,
                 75 g of H₂C₂Cl₄ will be produced by  =  X L of Cl₂

Solving for X,
                      X  =  (44.8 L × 75 g) ÷ 167.84 g

                      X  =  20 L of Cl₂

Its a hope this