The standard molar heat of vaporization for water is 40.79 kj/mol. how much energy would be required to vaporize 5.00 mol h2o

             203.95 kJ

Solution:
               Heat of vaporization is the amount of energy which is required to convert a substance from liquid state to gas state. In given problem it is given that for 1 mole of water (18 g) 40.79 kJ heat is required to convert it into steam, and for 5 moles of H₂O (90 g) the amount of heat required is calculated as,

As

                         1 mole of water requires 40.79 kJ heat,

So,

                                           5 mole of water will require,

                                      =  (5 mol × 40.79 kJ) ÷ 1 mol

                                      =  203.95 kJ

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Hello thereone of the following properties was originally used to arrange elements on the periodic table, but is no longer used to organize the modern version. which property fits this description? answer: atomic mass  was originally used to arrange elements on the periodic table, but is no longer used to organize the modern version.