What is the pressure exerted by 5.00 moles of nitrogen gas contained in a 30.0 liter container at 25.0 °c?

Given: number of moles of N2 = 5
volume of container = 30 l
temperature = 25 oC = 298 K

Also, we know that R = gas consant = 0.082 L atm mol-1 K-1

Now from ideal gas equation we have,

PV = nRT
∴ P = nRT/V
      = (5 X 0.082 X 298)/30
      = 4.07 atm.

Thus, pressure exerted by gas is 4.07 atm 

Ok where is the image ?