Calculate the amounts requested if 3.30 mol fe2o3 completely react according to the following equation. fe2o3 + 2al --> 2fe + al2o3 a. moles of aluminum needed b. moles of iron formed c. moles of aluminum oxide formed

A. Moles of Aluminum needed;

Reaction is as follow,

                                Fe₂O₃ + 2 Al      →    2 Fe + Al₂O₃ 
According to eq,

                              1 mole Fe₂O₃ required  =  2 mole of Al
So,
                       3.30 mol Fe₂O₃ will require  =  X moles of Al

Solving for X,
                     X  =  (2 mol × 3.30 mol) ÷ 1 mol

                     X  =  6.6 mol of Al

B. Moles of Iron formed:

According to eq,

                              1 mole Fe₂O₃ produced  =  2 mole of Fe
So,
                       3.30 mol Fe₂O₃ will produce  =  X moles of Fe

Solving for X,
                     X  =  (2 mol × 3.30 mol) ÷ 1 mol

                     X  =  6.6 mol of Fe

C. Moles of Aluminum Oxide formed:

According to eq,

                              1 mole Fe₂O₃ produced  =  1 mole of Al₂O₃
So,
                       3.30 mol Fe₂O₃ will produce  =  X moles of Al₂O₃

Solving for X,
                     X  =  (1 mol × 3.30 mol) ÷ 1 mol

                     X  =  3.30 mol of Al₂O₃

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.