How much 0.85 m hcl solution can be made by diluting 250 ml of 10 m hcl?

Answer is:  2940 mL of the HCL solution.

c₁(HCl) = 10.0 M.

V₂(AgNO₃) = ?.
c₂(AgNO₃) = 0.85 M.
V₁(AgNO₃) = 250 mL ÷ 1000 mL/L = 0.25 L.

c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₂(HCl) = c₁ · V₁ ÷ c₂.

V₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.

V₂(HCl) = 2.94 L · 1000 mL = 2940 mL.

it is stable as it is in group 0 which have full outer shells of electrons

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.