An experimental container has volume of 13000 l has an internal pressure of 1.38 atm. if the pressure inside the container becomes 250 atm, what would the new volume have to be ? assume all other properties remain constant ?

The  new  volume  is 71.76  L

calculation

 The new  volume  is  calculated using  the Boyle's  law  formula

that  is  P1V1=P2V2  where,

P1=1.38 atm

V1= 13000  L

P2  =250 atm

V2= ?

make V2  the   subject of the formula   by diving both side by P2

V2= P1V1/ P2

v2=( 1.38  atm  x 13000 L)  / 250 atm = 71.76 L

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so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer