Suppose you wish to make 0.879 l of 0.250 m silver nitrate by diluting a stock solution of 0.675 m silver nitrate. how many milliliters of the stock solution would you need to use?

Answer is: 325.5 mL of the stock solution.

c₁(AgNO₃) = 0.675 M.

V₂(AgNO₃) = 0.879 L.
c₂(AgNO₃) = 0.250 M.
V₁(AgNO₃) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₁(AgNO₃) = c₂ · V₂ ÷ c₁.
V₁(AgNO₃) = 0.250 M · 0.879 L ÷ 0.675 M.
V₁(AgNO₃) = 0.325 L · 1000 mL = 325 mL.

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