On September 1, Ziegler Corporation had 60,000 shares of $5 par value common stock, and $180,000 of retained earnings. On that date, when the market price of the stock is $15 per share, the corporation issues a 2-for-1 stock split. The general journal entry to record this transaction is:

After all revenue and expense accounts have been closed at the end of the fiscal year, income summary has a debit of $2,450,000 and a credit of $3,000,000. at the same date, retained earnings has a credit balance of $8,222,600, and dividends has a balance of $125,000. required: a. journalize the entries required to complete the closing of the accounts on december 31. refer to the chart of accounts for exact wording of account titles. b. determine the amount of retained earnings at the end of the period.

Neveready flashlights inc. needs $317,000 to take a cash discount of 3/15, net 70. a banker will loan the money for 55 days at an interest cost of $13,200. a. what is the effective rate on the bank loan? (use a 360-day year. do not round intermediate calculations. input your answer as a percent rounded to 2 decimal places.) b. how much would it cost (in percentage terms) if the firm did not take the cash discount but paid the bill in 70 days instead of 15 days? (use a 360-day year. do not round intermediate calculations. input your answer as a percent rounded to 2 decimal places.) c. should the firm borrow the money to take the discount? no yes d. if the banker requires a 20 percent compensating balance, how much must the firm borrow to end up with the $317,000? e-1. what would be the effective interest rate in part d if the interest charge for 55 days were $7,200?

Yowell company granted a sales discount of $360 to a customer when it collected the amount due on account. yowell uses the perpetual inventory system. which of the following answers reflects the effects on the financial statements of only the discount? assets = liab. + equity rev. − exp. = net inc. cash flow a. (360 ) = na + (360 ) (360 ) − na = (360 ) (360 ) oa b. na = (360 ) + 360 360 − na = 360 na c. (360 ) = na + (360 ) (360 ) − na = (360 ) na d. na = (360 ) + 360 360 − na = 360 na