Mary is deciding whether to book the cheaper flight home from college after her final exams, but she's unsure when her last exam will be. She thinks there is only a %10 chance that the exam will be scheduled after the last day she can get a seat on the cheaper flight. If it is and she has to cancel the flight, she will lose $150. If she can take the cheaper flight, she will save $50. a) If she books the cheaper flight, what can she expect to gain, on average? b) What is the standard deviation?

(a) Expected gain = 30

(b) Standard deviation = 66.03

Explanation:

From the question, we are given the following:

Probability of loss = 10%

Loss amount = $150

Probability of Saving = 100% - Probability of loss = 100% - 10% = 90%

Saving amount = $50

Therefore, we proceed as follows:

a) If she books the cheaper flight, what can she expect to gain, on average?

This can be calculated as follows:

Expected gain = (Probability of loss * (-Loss amount)) + (Probability of Saving * Saving amount) = (10% * (-150)) + (90% * 50) = -15 + 45 = 30

b) What is the standard deviation?

Standard deviation can be described as a measure of the amount of variation a set of values. This can be calculated from the variance as follows:

Variance = (Probability of loss * (-Loss amount - Expected gain)^2) + (Probability of Saving * (Saving amount - Expected gain)^2) = (10% * (-150 - 50)^2) + (90% * (50 - 30)^2) = (10% * (-200)^2) + (90% * (20)^2) = (10% * 40,000) + (90% * 400) = 4,000 + 360 = 4,360

Standard deviation = Variance^0.5 = 4,360^0.5 = 66.03

b

explanation:

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(b) management: leadership