Problem 5.3. A stock that does not pay dividend is trading at $100. The stock price will increase by 10% or decrease by 10% in one year. After that, the stock price will increase or decrease by 20% in the second year. The risk-free interest rate is 5% per annum with continuous compounding. Value a two-year American put option with strike price of $102. Note that risk-neutral probabilities or replicating portfolios may differ across two periods. You must also check for early exercise.

Visburg concrete company pours concrete slabs for single-family dwellings. lancing construction company, which operates outside visburg's normal sales territory, asks visburg to pour 40 slabs for lancing's new development of homes. visburg has the capacity to build 300 slabs and is presently working on 250 of them. lancing is willing to pay only $3, 300 per slab. visburg estimates the cost of a typical job to include unit-level materials, $1, 440: unit-level labor, $720: and an allocated portion of facility-level overhead, $1, 200. required calculate the contribution to profit from the special order. should visburg accept or reject the special order to pour 40 slabs for $3, 300 each?

He taylor company sells music systems. each music system costs the company $100 and will be sold to the public for $250. in year one, the company sells 100 gift cards to customers for $250 each ($25,000 in total). these cards are valid for just one year, and company officials expect them to all be redeemed. in year two, only 96 of the cards are returned. what amount of net income does the company report for year two in connection with these cards? a. $15,000b. $15,400c. $15,500d. $15,800

Myflvs -question 3 multiple choice worth 2 points)(10.04 hc)in panama city in january, high tide was at midnight. the water level at high tide was 9 feet and1 foot at low tide. assuming the next high tide is exactly 12 hours later and that the height of thewater can be modeled by a cosine curve, find an equation for water level in january for panamacity as a function of time (t).of(t) = 4 + 5of(t) = 5 cost + 4o 460) = 5 cos 1+ 4of(0) = 4 cos + 5