Rachel Dawkins has $26,000 invested in stock A and stock B. Stock A currently sells for $50 a share and stock B sells for $60 a share. If stock B doubles in value and stock A goes up 50%, her stock will be worth $42,000. How many shares of each stock does she own?

The Stock A = 400 and Stock B = 100

Explanation:

From the question given, we solve the problem as stated

Rachel invested $26,000 in stock A and stock B at prices of  $50 and $60 respectively.  

The first equation is given as:

26,000 = A50 + B60  

Then,

After a while, the stock A increases by 50% this means that,

the value of stock A currently is (50 x 150%) = $75

The stock B increases in value this means,

The current value of stock B  is (60 x 2) = $120

The total stock both are worth is $42,000.  

Thus,

The second equation becomes:

42,000 = A75 + B120  

We now have 2 equations.

The Equation 1  is denoted as:

26,000 = A50 + B60 (equation 1)

The equation 2 is denoted as:

42,000 = A75 + B120 (equation 2)

To  Further  solve this, we multiply equation 1 by -2,

Which is,

(-2 x 26,000) = (-2 x A50) + (-2 x B60)

52,000 = -A100 - B120 (equation 3)

Solve equation 2 and 3 to get the value of A:

42,000 = A75 + B120

-52,000 = -A100 - B120

-10,000 = -A25

A = -10,000/-25

A= 400

Substitute the value of A in any of the  equation to get B,  

So,

26,000 = A50 + B60

26,000 = (400)50 + B60

 26,000 = 20,000 + B60

B60 = 26,000 - 20,000

 B60 = 6,000

 B = 6,000/60

Therefore,  B = 100

if you use only 25 for your entertainment and only 200 for the groceries that you really need and take out the 50 per month for the computer then that should be enough

reducing the scale of the market for a new product.