A fabrication cell at Spradley's Sprockets uses the pull method to supply gears to an assembly line. George Jitson is in charge of the assembly line, which requires 559 gears per day. Containers typically wait 1.2 day in the fabrication cell. Each container holds 60 gears, and one container requires 2.2 day in machine time. Setup times are negligible. If the policy variable for unforeseen contingencies is set at 0.04, how many containers should Jitson authorize for the gear replenishment system?

The correct answer is 33 containers.

Explanation:

The details below are provided in the question:

Wait time in the fabrication cell (w) = 1.2

Daily demand of gears (d) = 559

Policy variable for unforeseen contingencies  $ ( α )  = 0.04

Machine time (m) = 2.2 days

Contained size (s) = 60

Therefore, number of containers (N) Jitson authorize for the gear replenishment system will be calculated as;

N = d(w + m) (1 + α) / s

N = 559(1.2 +2.2) (1 + 0.04) / 60

N = 559 (3.4) (1.04) / 60

N =  1976.624 / 60

N = 32.94

Therefore, approximately 33 containers should Jitson authorize for gear replenishment system.

answer; standing committee;

i might look it up later.