Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, the first having a mass of 275000 kg and a velocity of 0.325 m/s in the horizontal direction, and the second having a mass of 55000 kg and a velocity of -0.135 m/s in the horizontal direction.
What is their final velocity?

0.248 m/s

Explanation:

Using the Law Conservation of Linear Momentum

m₁v₁+m₂v₂=(m₁+m₂)V

Where:

m₁= mass of first train

m₂=mass of second train

v₁= velocity of first train

v₂ = Velocity of Second Train

V=Final Velocity after Collision

m₁= 275000 kg

m₂=55000 kg

v₁= 0.325 m/s

v₂ = -0.135 m/s

m₁v₁+m₂v₂=(m₁+m₂)V

(275000X0.325)+(55000X-0.135) = (275000+55000)V

89375-7425=330000V

81950=330000V

V= 81950/330000= 0.2483 m/s.

The Final Velocity, V of the trains after collision is 0.2483 m/s

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