"On average, a customer waits 8 minutes in a queue and customers arrive at a rate of 15 per hour. What is the average number of customers waiting according to the single-server queue model? "

A consumer is the beneficiary of a commodity, service, product, or idea gained from a seller, vendor, or supplier via a financial transaction or exchange for money or some other emoluments in sales, commerce, and economics.

The average number of customers waiting according to the single-server queue model is 2.

The formula for determining Average Waiting Time under the Single-Server Queue Model, as derived from the question, is as follows:

(Average Number of Customers in Queue)

Average Waiting Time is a mathematical symbol that is spelled Lambda and relates to the Rate of Arrive.

We have a Delay of 8 minutes

We have (Average Rate of Arrival) = 15 people every hour (60 minutes )which is 15/60= 0.25.

Assume that the average number of customers waiting in line is C.

By adding the multiple aspects above, our formula now becomes 8 = C/0.25

We cross multiply to obtain. As a result, we have:

C = 0.25 x 8 C = 2

Therefore the Average No. of Customers waiting according to the single-server queue model given the above conditions is 2.

To know more about the number of customers, refer to the link below:

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The Answer is A) 2

Explanation:

Drawing details from the question, the formula for calculating Average Waiting Time under the Single -Server Queue Model is given as:

Average  Waiting Time = (Average No of customers waiting in line)  

                                                                        λ

> λ is a mathematical symbol pronounced Lambda and here refers to Rate of Arrival.

> We have Average Waiting Time = 8

> We have λ (Average Rate of Arrival) = 15 People every hour (that is 60 Minutes)

> that is 15/60= 0.25

Therefore λ = 0.25

> Lets assume that Average No. of Customers Waiting in Line is C

Our formula (by substituting the various factors above now becomes

8 = C/0.25

To get, we cross multiply. So we have:

C = 8 x 0.25

C = 2 thefore the Average No. of Customers waiting according to the single-server queue model given the above conditions is 2.

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