The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 × 106 Btu/h. The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 5200 h a year intermittently. Taking the unit cost of energy to be $23/106 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.

Solution:

Given Information,

Heat input is ( ) = 5.5 × Btu/h

Combustion efficiency of the boiler () = 0.7

Combustion efficiency after turn up () = 0.8

Operation Hour (t) = 5200h

Unit cost (c) =

Calculate heat output from the boiler   = x

                                                                      = 5.5 x x 0.7

                                                                      = 3.85 x Btu/h

Calculate the heat input to the boiler after the tune-up

= /

               = 3.85 x / 0.8

               = 4.8125  x Btu/h

Calculate the saved energy after the tune-up

= -

                 = 5.5 x - 4.8125  x Btu/h

                 = 0.6875  x Btu/h

Calculate the annual energy saving ( )

= x t

           = ( 0.6875  x Btu/h ) ( 5200 hr/yr)

           = 3575 x Btu/h

Calculate the annual cost saving

Annual cost saving = x Unit cost

                                = 3575 x Btu/h x

                                = 82225

dunce cap 4life lollolol

answer: 11/12

step-by-step explanation: 4 1/4 and 3 1/3 is equivalent to 4 3/12 and 3 4/12. 4 3/12 - 3 4/12 =11/12