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Business, 26.11.2019 03:31 iamabouttofail

Let x1, be independent and identically distributed random variables, each with expected value ? = e[xi] = 2 and variance \sigma ^2 = var(xi) = 4. find an upper bound for p(x1+x2+···+x144 > 144) using the following steps:

(a) let z=x1+ x2++x144, and use rules of expectation and variance to find e[z]and var[z].
(b) let a be the difference between 144 and e[z].
(c) apply chebychev's inequality to z using the number a.
(d) use the fact that z is symmetrically distributed about its mean to connect your answer to (c) to the original question. (hint: draw a symmetric density curve for z, and mark the values e[z], (e[z]+a) and (e[z]? a.)
label regions in the graph with their corresponding probabilities.)

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