Lindsay electronics, a small manufacturer of electronic research equipment, has approximately 6 comma 800 items in its inventory and has hired joan blasco-paul to manage its inventory. joan has determined that 8% of the items in inventory are a items, 33% are b items, and 59% are c items. she would like to set up a system in which all a items are counted monthly (every 19 working days), all b items are counted quarterly (every 60 working days), and all c items are counted semiannually (every 118 working days). how many items need to be counted each day? the total number of items that need to be counted each day is nothing items (round your response to the nearest whole number).

100 items need to be counted each day.

Explanation:

Of the 6,800 items, 544 are A items (0.08 * 6,800), 2,244 are B items (0.33 * 6,800) and 4,012 are C items (0.59 * 6,800). If you want to count every day the same number of items, you have to divide the number of items A, B and C for the days between being counted twice. So, if you have to count each day a number of items A, the amount is 544/19 working days, that is 28.6315789. The same with B (2,244/60 = 37.4) and with C (4,012/118 = 34). Each day, you have to count 28.63 A plus 37.4 B plus 34 C. 28.63+37.4+34=100.03.

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