In humans, a cleft chin is dominant and no-cleft is recessive. what will the generations look like? assume that mendel’s method of crossing two true breeding parents with opposite traits is followed. check all that apply. the p generation, f1 generation, and f2 generation will have all cleft chins. the p generation, f1 generation, and f2 generation will have all no-cleft chins. the p generation and f1 generation will have all cleft chins. the f1 generation will have all cleft chins. the p generation and f2 generation will have all no-cleft chins. the p generation and f2 generation will have cleft chins and no-cleft chins. the p generation, f1 generation, and f2 generation will have cleft chins and no-cleft chins.

The generations will look like the following:

Therefore; the generations will look like the following:

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The answers would be:

The F1 generation will have all cleft chins.

The P generation and F2 generation will have cleft chins and no-cleft chins.

If you'd like to know why:

Using Mendel's method of crossing:

Let C be the dominant trait and c be the recessive trait.

We do first the P generation. True breeding would been that both are homozygous, one is dominant and the other recessive.

CC x cc (This means in the P generation, we have both no cleft chins and cleft chins)

The Punnet for that would look like this:

      c         c

C  Cc       Cc

C  Cc       Cc

F1 generation would then all have cleft chins. If the genotype of the same trait consists of at least 1 dominant allele, then the dominant trait will be expressed. In this case, cleft chin.

Now we do the breading of F1 generation. So since they are all Cc, then the cross would be between two Cc.

Cc x Cc (F1 Generation)

The Punnet for that would look like this.

     C       c

C  CC    Cc

c   Cc     cc

As you can see we have a homozygous recessive in the mix now and the others are all dominant. So we can say that the F2 generation is a mix of cleft- and no cleft chin.

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