A tube with a membrane covering the bottom is placed in a beaker. The membrane allows water to flow through but not salt or glucose. The tube contains an aqueous solution with 4% salt and 20% glucose and the beaker contains an aqueous solution with 12% salt and 6% glucose. How could you describe the solution in the beaker compared to the solution in the tube

The solution in the tube is hypertonic to the solution in the beaker.

Explanation:

To compare the solutions, find the total amount of solutes in both the tube and beaker.

The tube has 4% salt and 20% glucose, so it has 24% solute.

The beaker has 12% salt and 6% glucose, so it has 18% solute.

Since 24 is larger than 18, this means the tube has more solute.

Since the tube has more solute and less water compared to the beaker, it is hypertonic to the beaker.

So, the answer is that the solution in the tube is hypertonic to the solution in the beaker.

i believe the answer is c

the answers are as following:

1. c. double helix, nucleosome, coil, supercoil, chromosome

2. b. g2 phase, preparation for mitosis

3. d. interphase consists of the g1, s, and g2 phases

4. c. metaphase

5. a. chromosomes are duplicated before cell division so that each new daughter cell has a complete set