Ablack rooster mates with a white hen. based on their genotypes, the chance that the offspring will be checkered is 100 percent.
what is the rooster’s genotype? a) bb b) bb c) bb d) bw
what is the hen’s genotype? a) ww b) ww c) ww d) bw

The rooster’s genotype is BB while the hen’s genotype is WW.

CO-DOMINANCE:

According to this question, a black rooster mates with a white hen to give an 100% checkered offsprings. This means that all of the offsprings are checkered. The checkered offsprings are hybrids of the two parental phenotypes i.e. black rooster and white hen. This means that the checkered offspring has a heterozygous genotype. To get an 100% heterozygous genotype in the F1 generation i.e. BW, both parents have to be homzygous, making this kind of inheritance an co-dominance. Therefore, the genotype of the black rooster will be homzygous i.e. BB while the genotype of the white hen will also be homzygous i.e. WW.

The cross can be find attached as an image.

Therefore, the rooster’s genotype is BB while the hen’s genotype is WW.

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Well, since the phenotype is checkered, we assume that there is codominance where offspring phenotype is a mix of the parents' phenotypes.  If the offspring phenotype is a blend between the two parents', then there is incomplete dominance.

Genotypes of codominant parents is usually represented by upper case letters B and W, and the mixed genotype would be BW.

Since the genotype BW is 100%, the rooster's genotype can only be BB and the hen's genotype can only be WW to result in 100% BW.

The correspond Punnett square is therefore
       B     B
W  BW  BW
W  BW  BW

By the way, apparently that this example is academically made up, there are no checkered chickens.  I don't know if this is true, since I don't raise enough chickens to verify this.  :)

No because the eaeht is on a 23.5 degree axis tilt and so when it is winter the northern hemisphere is pointing away from the sun and the soutubern hemisphere is pointing toward the sun