Aparent that is heterozygous for both traits (aabb) can create how many different allele possibilities.

Distribute the A to the B and the b, then the a to the B and the b. You should get four different possible combinations: AB Ab aB ab. These would then be used to set up one side of a punnett square, and the other parent's genotype would be set up the same, then put on the other side of the punnett square. 

The answer would be simply interphase and mitosis