Na dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and wrinkled seeds?
r=round
r = wrinkled
y = yellow
y = green

1/16

Explanation:

See the Punnett square diagram to observe the result of the cross between the round and yellow plants (RrYy X RrYy).

Since round (R) is dominant over wrinkled (r) and yellow (Y) is dominant over y (green), the plant with genotype rryy would have wrinkled and green phenotype as these are recessive characters.

From the given cross in the Punnett square, we can observe that there is a total of 16 possible progenies and out of these only 1 has the wrinkled and green phenotype.

Therefore the probability is 1/16.

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