2. a gas has a pressure of 0.410 atm and a volume of 32 l. at what pressure would the volume of
the gas change to 28l?

For this item, we assume that the gas behaves ideally such that it follows the ideal gas law and the ideal gas equation is applicable.
                                    PV = nRT 
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. When the right-hand side of the equation is constant, there exist a relationship that,
                                    P₁V₁ = P₂V₂
Substituting the given,
                                 (0.410 atm)(32 L) = (P₂)(28 L)
The value of P₂ is equal to 0.4686 atm. 

Ithink the answer is d.