In humans tongue rolling is dominant to the inability to tongue roll. if a heterozygous tongue roller and a non-tongue roller have a child, what are the chances the child will be a non-tongue roller? a. 0 b. 0.25 c. 0.5 d. 0.75

The chances of a child being non - tongue roller is

Explanation:

Let the allele for dominant "tongue rolling trait" be represented by "T"

The allele for recessive  "non-tongue rolling trait" be represented by "t"

The genotype of a heterozygous tongue rolling parent will be "Tt"

The genotype of a homozygous non- tongue rolling parent will be "tt"

If a cross is carried out between these two individuals , the offspring  produced are as shown in the punnet square below-

Tt

tTttt

tTttt

So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"

So the chances that a child will be a non-tongue roller are

Where , "4" represents the total number of offsprings produced

answer; /// i believe that the correct answer is; ///a combination of the birth and death