How old is a bone in which the carbon-14 in it has undergone 3 half-lives? a) 11,400 years old eliminate b) 17,100 years old c) 34,200 years old d) 57,000 years old

The answer is B 17,100,

(1,250 is the third half life of carbon 14)

Explanation:

The carbon 14 remaining in 0 years is 10,000. The carbon 14 remaining after its first half life would be 5,000, which is 5,700 years after death, the second half live would be 2,500 which is 11,400 years after death, the third half life is 1,250 which is 17,100 years after death. (divide the full life 10,000 by two)

Hope This Helped

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