Parents that are heterozygous for having freckles (dominant) are crossed. which represents the ratio of their offspring?
twenty-five percent have freckles.
twenty-five percent are ff.
seventy-five percent have freckles.
seventy-five percent are ff.

Seventy-five percent (75%) have freckles.

Explanation:

This is a cross involving a single gene coding for possession or not of freckles in humans. According to the question, possessing freckles (allele F) is dominant over not possessing it (allele f). Therefore, a heterozygous human will have a Ff genotype and possess freckles.

Crossing two heterozygous parents will result in four possible offsprings as follows: 1 offspring will be homozygous dominant (FF), 2 offsprings will be heterozygous dominant (Ff), 1 offspring will be homozygous recessive (ff). The two dominant offsprings i.e. 3 of the offsprings (FF and Ff) will phenotypically possess freckles, Hence, the percentage of offsprings that have freckes is 3/4 × 100 = 75%. (See attached image)

sadness is not good

explanation:

label a.   prophase

label b. metaphase

label c: anaphase

label d: telophase