Estimate the electric field in the membrane wall of a living cell. Assume the wall is 14 nmnm thick and has a potential of 0.11 VV across it.

The electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

Explanation:

Given;

thickness of the membrane wall, d = 14 nm = 14 x 10⁻⁹ m

potential of the membrane wall, V = 0.11 V

The electric field in the membrane wall of a living cell is calculated as;

Therefore, the electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

the diploid number of chromosomes is sometimes represented by the symbol 2n. for the fruit fly, the diploid number is 8, which can be written as 2n = 8, where n represents twice the number of chromosomes in a sperm or egg cell.

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.