How many grams of sucrose(342g/mole) are needed to make 1L of 1M solution?

342grams

Explanation:

The mass in grams needed to make a solution can be calculated by first calculating its molarity using the below formula;

Molarity = number of moles (mol)/volume (L)

number of moles (n) = volume × molarity

n = 1M × 1L

n = 1mol.

Using mole = mass ÷ molar mass

Molar mass of sucrose (C12H22O11) = 342g/mol.

1 = mass/342

mass = 342 × 1

mass = 342grams of sucrose are needed to make 1L of 1M solution.

not sure if this what   you'r looking for would be percent composition