To approximate the actual concentration of enzymes in a bacterial cell, assume that the cell contains equal concentrations of 1,000 different enzymes in solution in the cytosol and that each protein has a molecular weight of 100,000. Assume also that the bacterial cell is a cylinder (diameter 1.0 m, height 2.0 m), that the cytosol (specific gravity 1.20) is 20% soluble protein by weight, and that the soluble protein consists entirely of enzymes. Calculate the average molar concentration of each enzyme in this hypothetical cell.

2.4 × 10⁻⁶ M

Explanation:

Molar concentration = no of moles of solute (enzymes)/volume of solvent(cystosol)

Let V = volume of solvent = volume of cystosol = πd²h/4 where d = diameter of cell = 1.0 m and h = height of cell = 2.0 m

Concentration of enzymes, C = n/V where n = no of moles of enzymes

Also, n = m/M where m = mass of all enzymes and M = molecular weight of protein = 100,000

Note that the solvent for the enzymes is cystosol, since they are dissolved in it.

Density of cystosol,ρ = specific gravity of cystosol in g/cm³ = 1.20 g/cm³.

Now, ρ = m'/V where m = mass of cystosol and V = volume of cystosol

m' = ρV

m' = 1.20V

Given that 20 % of the cystosol is protein and all protein are enzymes, the mass of enzymes is thus m = 0.2m' = 0.2 × 1.20V = 0.24V

C = n/V

= m/MV

= 0.24V/100000V

= 2.4 × 10⁻⁶ mol/cm³

= 2.4 × 10⁻³ mol/dm³

= 2.4 × 10⁻³ M

This is the concentration of all the 1000 enzymes.

So, the concentration of one enzyme is 2.4 × 10⁻³/1000 M = 2.4 × 10⁻⁶ M

both male and female gametes are produced by meiosis of the germ cells. therefore, both male and female gametes are haploid. one male and one female gamete unite during the fertilization to form the diploid zygote. in seed bearing plants, pollen grain is the male gametophyte, which produces sperm cells.