An individual has the genotype Aa Bb CC Dd ee FF. How many different types of gametes could it produce in terms of unique allelic combinations of these genes?

64

Explanation:

The individual in this question with genotype: Aa Bb CC Dd ee FF has six (6) different traits encoded by six (6) genes. The diploid number of the organism in this question is 12, however, the number of possible allelic combinations in each gamete can be calculated by using 2^n where n = haploid number of chromosome or number of allele that can be in one gamete.

Using this simple formula, 6 possible alleles can be in the gamete of this organism with the above genotype, hence, the individual can produce 2^6 = 64 different types of gametes in terms of unique allelic combinations of these 6 genes.

hydroxyl -oh

alcohols, always polar, can form hydrogen bonds with h2o molecules

carboxyl -cooh  

cargoxylic acids, has acidic properties which is a source of hydrogen ions, found in cells in ionized for with a charge of oh-1

carbonyl > co

ketone if within skeleton, aldehyde if group is at the end of skeleton, k & a may be structural isomers, it determines 2 sugars (ketose & aldose)

amino -nh2

amines, acts as a base, it can pick up h+ ions from surrounding solution, ionized with charge of 1+

methyl ch2

addition to rna/dna affects and gene expression

phosphate -opo3 ²⁻

organic phosphates, contributes to negative charge to, molecule that it is a part of, and potential to react with h20

sulfhydryl -sh

thiols, cross-linking stabilize the protein, and it is structure

name and explain one of the event that occurs during meiosis that increases the variation in offspring even more than simple reproduction?