201,600J is supplied to 600g of water with a specific heat capacity of 4200J/kg°C. What is the change in temperature?

80°C

Explanation:

The change in temperature can be calculated my using the specific heat capacity equation as follows;

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (kg)

c = specific heat capacity of water (J/kg°C)

∆T = change in temperature (°C)

According to this question, Q = 201,600J, m = 600g = 600/1000 = 0.6kg, c of water = 4200J/kg°C

Using Q = m × c × ∆T

201600 = 0.6 × 4200 × ∆T

201600 = 2520 × ∆T

∆T = 201600 ÷ 2520

∆T = 80

Change in temperature (difference in initial and final temperature) is therefore 80°C

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