C + O2 = CO2 If 12g of C reacts with 40g of O2, How much CO2 will be formed? State the law which governs your answer. (5 Mark)

PLEASE ANSWER FAST​

44 g CO₂

Explanation:

The chemical equation for the reaction is:

C(s) + O₂(g) → CO₂(g)

Thus, 1 mol of C(s) reacts with 1 mol of O₂. We convert the moles to grams by using the molecular weight of each compound (C= 12 g/mol; O₂= 32 g/mol):

1 mol C(s) = 12 g/mol x 1 mol = 12 g

1 mol O₂= 32 g/mol x 1 mol = 32 g

The stoichiometric ratio C(s)/O₂ is 12 g C/32 g O₂. We have 40 g of O₂, so it will be consumed:

40 g O₂ x 12 g C/32 g O₂= 15 g C(s)

And we have 12 g. Thus, the limiting reactant is C(s).

Now, we use the limiting reactant to calculate the mass of product produced (CO₂)

Molecular weight CO₂ = 12 g/mol x 1 C + (16 g/mol x 2 O) = 44 g/mol

1 mol CO₂ = 44 g/mol x 1 mol = 44 g

So, 44 grams of CO₂ are produced from 12 g of C(s) (44 g CO₂/12 g C). So, the amount produced when 12 g of C(s) reacts with 40 g O₂ is:

12 g C(s) x 44 g CO₂/12 g C(s) = 44 g

explanation:

the universal gravitation equation. since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. if the mass of one of the objects is doubled, then the force of gravity between them is doubled.

ans.

gregor john mendel is known for study of inheritance in pea plants. he used garden pea plant for his study, having alternative traits for various characters. he performed cross-breeding in pea plants to check how characters are transmitted between parents to offspring, such as cross between pure tall and pure dwarf plant. mendel studied the inheritance patterns in pea plants for various generations.

thus, the correct answer includes options and f).