In cocker spaniels, black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s). In the F 2 generation of a cross between BB ss with bb SS, what fraction of the offspring would be expected to be black and spotted

The correct answer is -3/16

Explanation:

The cross between BBss and bbSS In cocker spaniels will form gametes that are - Bs and bS. As it is given that  black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s) then f1 gen would be :

      Bs      Bs

bS BbSs  BbSs

bS  BbSs  BbSs

Now F2 generation;

       BS        Bs        bS        bs

BS   BBSS   BBSs   BbSS   BbSs

Bs   BBSs    BBss   BbSs   Bbss

bS   BbSS   BbSs   bbSS    bbSs

bs   BbSs   Bbss   bbSs     bbss

Here black-spotted that is possible only in two cases, BBss or Bbss, are 3/16

what is the aerea shown

explanation:

raits that your monster will have. the dna code for each trait is given, so you will need to go through the process of transcription and translation to determine what protein is being made and then match that with the corresponding trait. you may even include a picture of your monster if you are feeling creati