A chemist reacts 128.95 g of Fe3N2 and 32.34 g of Al as shown below. Fe3N2 + Al --> AlN + Fe

Part a) Calculate the maxium mass of AlN that can be produced.
Part b) Identify the limiting reactant.
Part c) Calculate the maximum mass of Fe that can be produced from this reaction.
Part d) When complete, the reaction actually produced 99.02 g of Fe. Calculate the percent yield.

Select all answer choices that apply to questions a-d.
Note: calculated values are rounded to 2 decimal places.
Group of answer choices

110.48

100.43

Fe3N2

108.92

98.59

49.14

Al

54.05