Consider a cross between two Brassic rap parent plants known to be heterozygos tall. Using a punnett square to solve this cross and break down the expected genotypc and phenotyic results. Draw a punet square here

Genotypic results:
Homzygous Dominant:
Heterzygous:
Homzygous Recessive:
Phenotypc results:
Tall:

Genotypic results: 1 (TT):2 (Tt) :1 (tt)

Homzygous Dominant: 1/4

Heterozygous: 1/2

Homzygous Recessive: 1/4

Phenotypc results: 3 tall: 1 short

Tall: 3/4

Short: 1/4

Explanation:

This question involves a gene coding for height. The alelle for tallness (T) is dominant over the allele for shortness (t). According to this question, a cross between two Brassic rap parent plants known to be heterozygos tall (Tt) is performed.

Each parent will produce gametes T and t. Using these gametes in a punnet square (see attached image), the following offsprings will be produced:

TT (1), Tt (2), and tt (1)

Based on this result, the following results are obtained:

Genotypic results: 1 (TT):2 (Tt) :1 (tt)

Homzygous Dominant: 1/4

Heterozygous: 1/2

Homzygous Recessive: 1/4

Phenotypc results: 3 tall: 1 short

Tall: 3/4

Short: 1/4

a. suckling by young

b. hypothalamus

c. dopamine

d. trh

e. anterior pituitary

f. mammary glands

g. milk production