If the original strand reads ATT-CCC-GCA what is the complementary strand?

Explanation:

Problem Set 4 Answers

1a. The template DNA strand, from which the mRNA is synthesized, is 5’ CAAACTACCCTGGGTTGCCAT 3’

(RNA synthesis proceeds in a 5’ à 3’ direction, so the template strand and the mRNA will be complementary to each other)

b. The coding DNA strand, which is complementary to the template strand, is 5’ ATGGCAACCCAGGGTAGTTTG 3’

c. The sequence of the mRNA is 5’ AUGGCAACCCAGGGUAGUUUG 3’

(the sequence of the mRNA is complementary to the template strand and identical to the coding strand with U substituted for T)

d. The third codon is 5’ ACC 3’. Therefore, the corresponding anti-codon is 5’ GGU 3’

2. Below is a table for the genetic code:

T

C

A

G

T

TTT Phe (F)

TTC "

TTA Leu (L)

TTG "

TCT Ser (S)

TCC "

TCA "

TCG "

TAT Tyr (Y)

TAC "

TAA Stop

TAG Stop

TGT Cys (C)

TGC "

TGA Stop

TGG Trp (W)

C

CTT Leu (L)

CTC "

CTA "

CTG "

CCT Pro (P)

CCC "

CCA "

CCG "

CAT His (H)

CAC "

CAA Gln (Q)

CAG "

CGT Arg (R)

CGC "

CGA "

CGG "

A

ATT Ile (I)

ATC "

ATA "

ATG Met (M)

ACT Thr (T)

ACC "

ACA "

ACG "

AAT Asn (N)

AAC "

AAA Lys (K)

AAG "

AGT Ser (S)

AGC "

AGA Arg (R)

AGG "

G

GTT Val (V)

GTC "

GTA "

GTG "

GCT Ala (A)

GCC "

GCA "

GCG "

GAT Asp (D)

GAC "

GAA Glu (E)

GAG "

GGT Gly (G)

GGC "

GGA "

GGG "

a. The following codons can be mutated by one base to produce an amber codon:

CAG Gln

AAG Lys

GAG Glu

TCG Ser

TTG Leu

TGG Trp

TAA Stop

TAT Tyr

TAC Tyr