An object drops from a building and strikes the ground with a speed of 31m/s. How tall is the building?

49.0m

Explanation:

Given the following data;

U = 0m/s since it's a free fall

V = 31m/s

Also, since it's a free fall, a = g = 9.8m/s²

To find the height of the building, we would use the third equation of motion;

Where;

V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration due to gravity measured in meters per seconds square. S represents the height measured in meters.

Substituting the values into the equation, we have;

Simplifying, we have;

S = 49.03 ≈ 49.0

Therefore, the building is 49.0m tall.

This type of galaxy is an approximately ellipsoidal shape and a smooth, nearly featureless image. they are the largest single star systems, in the universe and are built by the collisions of many smaller galaxies.

Ibelieve the answer is c.