Consider a hypothetical scenario in which the genes that determine body color, eye color, and wing type in fruit flies occur on the same chromosome. To determine the order of the three genes on the chromosome, a researcher looks at hundreds of flies and makes these observations: 90% of flies with red eyes have curly wings. 75% of flies with red eyes have black bodies, whereas the remaining 25% have brown bodies. 1% of flies have curly wings, white eyes, and black bodies. Based on these observations, what is the most probable location of each gene on the given chromosome

The most probable location on the chromosome of each gene is:

wing shape gene eye color gene body color gene

Explanation:

To know if two genes are linked, we must observe the progeny distribution. In a tri-hybrid cross, If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1:1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the heterozygote parent.

We can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. And simple recombinant gametes produced by the cross, which frequencies are intermediate.  

By comparing the parental and the double recombinant we will realize which is the allele that changes in position. The position of this gene is in the middle of the other two genes because in a double recombinant only the central gene changes position in the chromatid.

So, according to this knowledge and the available information in the problem we can estimate the position of the genes in the chromosome.

Phenotypic proportions:

90% of individuals are red-eyed and curly-winged. This is a high frequency, which means that this is the parental phenotype. The other parental phenotype must be white eyes and straight wings.

Flies with curly wings, white eyes, and black bodies represent the lower proportion (1%) so this phenotype must be the double recombinant.

Flies with red eyes and black bodies, and flyes with red eyes and brown bodies are intermediate in proportion, so they must be simple recombinant phenotypes.

Parental)

Red, Curly  

White, Straight

Double recombinant)

White, Curly, Black  

Red, Straight, Brown  

Simple recombinant)  

Red, Black

Red, Brown

In the chromatid, there are two regions, Region 1 (from the first gene to the gene in the middle), and region 2 (from the gene in the middle to the gene of the other extreme).

The fact that both simple recombinants are red, tells us that the eye color gene and the body color gene are together, and the recombination occurred either in region 1 or 2.  

We know that the double recombinant is White, Curly, Black. We also know that the eye color gene and the body color gene are together, so one of these two must be in the middle.

Parentals are red and curly, which means that the eye color gene and wing shape gene are also together. This leads us to assume that the eye color gene is in the middle.

Finally, the fact that the double recombinant is White, Curly, Black, and knowing that the eye color is in the middle and that both the extreme alleles change position, we can assume that the parental Red, Curly is also black, while the other parental is white, straight and brown. So:

Curly Red Black (90%)

Straight White Brown

Curly WhiteBrown

StraightRed Black (75%)

CurlyRedBrown (25%)

Straight WhiteBlack

CurlyWhiteBlack (1%)

StraightRedBrown    

it is either c or d and i know for sure it is not a or b

1. what is the relationship between the shape of an enzyme and the reactions they catalyze?

2. how does an enzyme inhibitor work?

separate your answers so i dont get confused : )