Each of two parents has the genotype blue/brown, which consists of the pair of alleles that determine eye color, and each parent contributes one of those alleles to a child. Assume that if the child has at least one blue allele, that color will dominate and the child's eye color will be blue. a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the brown/brown genotype? c. What is the probability that the child will have blue eye color?

See the answer below.

Explanation:

Let the allele for eye color be represented by A. Blue is dominant over brown eye color, hence, blue allele would be A while brown eye allele would be a.

Two parents have the genotype blue/brown which is equivalent to Aa.

                   Aa    x    Aa

    AA               2Aa                aa

 blue eyes     blue eyes         brown eyes

a. Different possible outcomes: AA blue eyes, Aa blue eyes, and aa brown eyes.

b. Probability of a child from the cross having brown/brown (aa) genotype = 1/4 or 25%

c. Probability that the child would have blue eye color = 3/4 or 75%

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