In a population of 200, 86 individuals express the recessive phenotype. What percent of the population would you predict would be heterozygous?
A. 65%
B. 55%
C. 35%
D. 45%

The correct option is;

D. 45%

Explanation:

From the Hardy- Weinberg law, we have;

p² + 2·p·q + q² = 1

p + q = 1

Where:

p = Dom inant allele frequency in the population

q = Recessive allele frequency in the population

p² = The percentage of individuals in the population that are hom ozygous dominant

q² = The percentage of individuals in the population that are homo zygous recessive

2×p×q = The percentage of hete rozyous individuals in the population

The number of individuals that express the recessive phenotype = 86

The number of individuals in the population = 200

The percentage of  individuals that express the recessive phenotype, q² = 86/200 = 0.43

Therefore;

q = √0.43 = 0.656

p + q = 1

p = 1 - q = 1 - 0.656= 0.344

∴ The frequency of  individuals that express the do minant phe notype, p = 0.344

The percentage of heterozyous individuals in the population = 2×p×q × 100 = 2 × 0.656 × 0.344 × 100 = 45.15% ≈ 45%

ya the other dude is right

the dna molecules have a negative charge because of the phosphate groups in their sugar-phosphate backbone, so they start moving through the matrix of the gel towards the positive pole. power is turned on and dna fragments migrate through gel (towards the positive electrode).

explanation: