The structural formula of an unsaturated fatty acid resembles the following diagram. A chain of 7 C atoms has the left end double-bonded above to O and single bonded below to O H. The fourth and fifth C are double-bonded to each other and have H above but not below; all other C's have H above and below, and the right-end C has H to the right. Which of these is a geometric isomer of the above compound? A chain of 7 C atoms has the left end bonded above to O H and double bonded below to O. The fourth and fifth C are double-bonded to each other and have H below but not above; all other C's have H above and below, and the right-end C has H to the right. A chain of 7 C atoms has H to the left, above, and below, except the third and fourth C are double-bonded to each other and only have O above; the final C in the chain has no H, but is double bonded above to O and single bonded below to O H. A chain of 7 C atoms has the left end double-bonded above to O and single bonded below to O H. The fourth and fifth C are double-bonded to each other. The fourth C has H above only, and the fifth C has H below only; all other C's have H above and below, and the right-end C has H to the right. A chain of C atoms has H above, below and to the right; the left most C has instead O double-bonded above and O H single-bonded below,